What is the equation of a line that passes through points (-3,0.5) and (3, -0.5)?A.) y = -1/6xB.) y = -6xC.) y = -1/6x + 1D.) y = -6x - 17.5

Answer:y=-1/6x + 0   or     y=-1/6x    (when b = 0 then you leave it out)Step-by-step explanation:Find the slope: -0.5 - 0.5/3 - (-3) = -1/6Find the y intercept (b): Plug in the x, y and m into y= mx + b0.5=(-3)(-1/6) + b0.5=1/2 + b0.5-0.5 = b (change the 1/2 into a decimal 0.5 to make it easier to subtract0=bNow plug in the m and the b that you just found into the equation y=mx+by=-1/6x + 0 or y=-1/6x    (when b = 0 then you leave it out)