An Isosceles triangle has single measures 55,55,and 70. The side across from the 70 angle is 10 inches long. How long are the other sides?
Accepted Solution
A:
Answer:8.717 both the sidesStep-by-step explanation:Given:Let ABC be the given triangle withangle A= 55angle B=55angle C= 70side across angle C, c= 10 inchesside across angle B, b =?aide across angle A,a=?Now using the law of sin to find a and b: a/sinA=c/sinC a= (c/sinC)(sinA) Putting the values: a= (10/sin70)(sin55) a= 8.717As the given triangle is isosceles so side a=bhence a=b= 8.717 inches !